If sin^-1x +sin^-1y =?/2 , then find the value (x+y)^2.

Range of sin^–1x is [-pi/2, pi/2].

Give that sin^-1x +sin^-1y = π

Each of sin^-1x, sin^-1x takes value of pi/2.

So,

x = 1, y = 1

Hence,

(x+y)^2

= 2^2

= 4