If the common difference of an AP is 5, then what is a18-a13?
5
20
25
30
Find the required value based on given information
Given, common difference is d=5
We know that the nth term of an A.P. is given by
an=a+n-1d
where,
a=firstterm
d=commondifference
an is the nth term
Therefore
a18-a13=a+17d-a+12d⇒a18-a13=5d⇒a18-a13=5×5⇒a18-a13=25
Hence, a18-a13=25,
So, the correct option is (C)
What is the common difference of an AP in which a18−a14=32? (a) 8 (b) -8 (c) 4 (d) -4