Question

If the point $(3,4)$ lies on the graph of the equation $3y=ax+7$, find the value of $a$?

Answer 1

Calculate the value of $a$:

It is given that $3y=ax+7$ is in linear equation form and $(3,4)$ satisfies the given equation.

Thus, the given equation will satisfy on substituting $x=3$ and $y=4$.

$$\begin{gathered} \Rightarrow 3\left(4\right)=a\left(3\right)+7 \\ \Rightarrow 12=3a+7 \\ \Rightarrow 3a=5 \\ \Rightarrow a=\frac{5}{3} \end{gathered}$$

Hence, the value of $a$ is $\frac{5}{3}$.