If x2+x3=5 then x=
Compute the required value.
Given : x2+x3=5.
Take LCM of the denominators on the left-hand side., we get
LCM (2,3)=6
So,3x+2x6=5⇒5x6=5
Divide both sides by 5.
⇒x6=1
Multiply both sides by 6.
⇒x=6
Hence, the value of x is 6.
Solve for x:x−23=2x7
If {x2−x2x,x≠0k,x=0 and if f is continuous at x=0,then k=?