Question

If $\left(x^{2}y+y^2+3\right)$ is subtracted from $\left(3x^{2}y+2y^2+5\right)$, then the coefficient of $y$ in the result is ________.

Answer 1

Compute the required value.

Given: $\left(x^{2}y+y^2+3\right)...\left(1\right)$

$\left(3x^{2}y+2y^2+5\right)...\left(2\right)$

Subtract expression $1$ from expression $2$, we get;

$$\begin{gathered} \Rightarrow \left(3x^{2}y+2y^2+5\right)-\left(x^{2}y+y^2+3\right)=x^{2}y(3-1)+y^2(2-1)+5-3 \\ \Rightarrow \left(3x^{2}y+2y^2+5\right)-\left(x^{2}y+y^2+3\right)=2x^{2}y+y^2+2 \end{gathered}$$

Hence, the coefficient of $y$ is $2x^2$.