In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is:
6
7
8
12
Explanation for correct option
The mid value of the class =10
Width of the interval =6
We know that
Lowerlimit=Midvalue-Width2
=10-62=10-3=7
Hence, the correct option is OptionB