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Question

In the figure, the tangents $ PQ$ and $ PR$ are drawn to a circle such that $ \angle RPQ = 30°$. A chord $ RS$ is drawn parallel to the tangent $ PQ$. Find the $ \angle RQS$.


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Solution

Step 1: State the given data and equate PQR & PRQ

As given, PQ and PR are the tangents to the circle.

RPQ=30°

And, RS is a chord such that RS||PQ.

Now, since PQ and PR are the tangents drawn from the same point.

So, PQ=PR

In PQR, using the property of isosceles triangles,

PQ=PR

PQR=PRQ ...(i)

Step 2: Calculate the value of PQR and PRQ

Now, Using the angle sum property in the PQR,

PQR+PRQ+RPQ=180°

PQR+PQR+RPQ=180° [Using equation (i)]

PQR+PQR+30°=180° RPQ=30°

2PQR+30°=180°

2PQR=180°-30°

2PQR=150°

PQR=150°2

PQR=75°

So, PRQ=PQR

PRQ=75°

Step 3: Calculate the value of SRQ and QSR

Since RS||PQ and QR is a transversal.

So, SRQ=PQR [alternate interior angles]

SRQ=75°

Now, according to the alternate segment theorem, the angle between a tangent and a chord of a circle is always equals to the angle made by the chord in the alternate segment of the circle.

So, QRP=QSR

Or, QSR=QRP

QSR=75° QRP=PRQ=75°

Step 4: Calculate the value of RQS

Applying the angle sum property in the QRS,

SRQ+RQS+QSR=180°

75°+RQS+75°=180°

150°+RQS=180°

RQS=180°-150°

RQS=30°

Hence, the value of RQS is 30°.


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