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Question

In how many ways can the letters of the word "PERMUTATIONS" be arranged so that there are always 4 letters between 'P' and 'S'?


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Solution

Step 1: Form the expression representing required number of ways

The given word is "PERMUTATIONS".

Also given that there should always be 4 letters between 'P' and 'S'.

Since there are a total of 12 letters in the word "PERMUTATIONS".

So, the number of places for each letter are 1,2,3,4,5,6,7,8,9,10,11,12.

According to the question, the possible places of 'P' and 'S' are 1,6,2,7,3,8,4,9,5,10,6,11 and 7,12.

So, the number of possible ways =7,

Also, the places of 'P' and 'S' can be interchanged,

So, the number of total possible ways =2×7=14

After fixing the places of 'P' and 'S', the remaining 10 places can be filled with the remaining 10 letters. So,

The required number of ways =P10102!

Step 2: Simplify the above expression

Using the rules of permutation, the above expression can be simplified as,

The required number of ways =P1010×12!

The required number of ways =10!10-10!×12! [Prn=n!(n-r)!]

The required number of ways =10×9×8×7×6×5×4×3×2×11×12×1

The required number of ways =1814400

Hence, the letters of the word "PERMUTATIONS" can be arranged in 1814400 ways so that there are always 4 letters between 'P' and 'S'.


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