CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the circuit shown in the figure, the current measured by the ammeter is


A

1A

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2A

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

3A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

3A


Step 1: Series LCR Circuit

We know that the current in a series LCR circuit impressed by an ac emf v=V0cosωt is given by

i=I0cosωt-ϕ,

Where I0=V0R2+ωL-1ωC2 and ϕ=tan-1ωL-1ωCR

The RMS current is Ir=VrR2+ωL-1ωC2, 1

Where Vr is the RMS voltage. Thus, Ir depends on the frequency ω of the impressed ac emf.

Step 2: Phasor Diagram

The given circuit can be represented in a phasor diagram as

Step 3: Calculate the Current

From the graph we get

100-602+VR2=Vnet

402+VR2=50

402+VR2=502

VR2=2500-1600

VR2=900

VR=30

Given that R=10Ω

I=VR

=3010=3A

Hence, the correct answer is option (C).


flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Series RLC
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon