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Question

In the reaction VO+Fe2O3FeO+V2O5, the equivalent weight of V2O5 is equal to its ______


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Solution

Step 1: Finding valence factor of V2O5

VO+2+Fe2O3+3FeO+2+V2O5+5

Oxidation number of V in VO = +2

Oxidation number of V in V2O5 = +5

Change in oxidation number of one V atom = 5-2=3

Change in oxidation number of two V atoms = 3×2=6

So, valence factor of V2O5 = 6

Step 2: Equivalent weight of V2O5

Equivalentweight=Molecularweightvalencefactor

Therefore, EquivalentweightofV2O5=Molecularweight6


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