In The Number Of Bond Pairs, Pi-bonds, And Lone Pairs On Atoms Respectively Are?
Explanation for the Correct Option:
Option(D)::-
Step 1: Calculating the number of Bonding pairs:
We know that the number of electrons in its valence shell of Xe= 8
Since oxygen has a valency of 2, thus for Oxygen atoms the number of sigma bonds = 1 for each
Also for 3 Oxygen atoms the number of double bonds each with the Xe atom = 1 for each
Whereas for the two fluorine atoms the number of sigma bonds = 1 for each
Thus in total, we can say that Xenon forms a number of bond pairs = 3 sigma bonds each with 3 Oxygen + 2 sigma bonds with = 5
And the number of bonds= 3 ( one with each Oxygen)
Step 2: Calculating the number of lone pairs:
The 8 electrons are used up in bond formation, 2 in bonding with the two fluorine atoms, and the remaining six are used in a bond formation with the three oxygen atoms.
Thus the no lone pairs on the atom = 0
Step 3: Calculating the total number of bonding in :
We can conclude that in , the number of bond pairs = 5,
The number of bonds = 3
The number of lone pairs = 0,
Which can be shown in the figure as;
Hence, In the number of bond pairs, pi-bonds, and lone pairs on Atoms Respectively are .