Question

In ${\mathrm{XeO}}_3{\mathrm{F}}_2$The Number Of Bond Pairs, Pi-bonds, And Lone Pairs On $\mathrm{Xe}$ Atoms Respectively Are?

• A. $4,2,2$
• B. $4,4,0$
• C. $5,2,0$
• D. $5,3,0$

Answer 1

The correct option is D

$5,3,0$

Explanation for the Correct Option:

Option(D):$5,3,0$:-

Step 1: Calculating the number of Bonding pairs:

We know that the number of electrons in its valence shell of Xe= 8

Since oxygen has a valency of 2, thus for Oxygen atoms the number of sigma bonds = 1 for each

Also for 3 Oxygen atoms the number of double bonds each with the Xe atom = 1 for each

Whereas for the two fluorine atoms the number of sigma bonds = 1 for each

Thus in total, we can say that Xenon forms a number of bond pairs = 3 sigma bonds each with 3 Oxygen + 2 sigma bonds with $\mathrm{Xe}$ = 5

And the number of $\mathrm{\pi }$ bonds= 3 ( one with each Oxygen)

Step 2: Calculating the number of lone pairs:

The 8 electrons are used up in bond formation, 2 in bonding with the two fluorine atoms, and the remaining six are used in a bond formation with the three oxygen atoms.

Thus the no lone pairs on the $\mathrm{Xe}$ atom = 0

Step 3: Calculating the total number of bonding in $\text{Xe}{\text{O}}_{\text{3}}{\text{F}}_{\text{2}}$:

We can conclude that in $\text{Xe}{\text{O}}_{\text{3}}{\text{F}}_{\text{2}}$, the number of bond pairs = 5,

The number of $\mathrm{\pi }$ bonds = 3

The number of lone pairs = 0,

Which can be shown in the figure as;

Hence, In ${\mathrm{XeO}}_3{\mathrm{F}}_2$the number of bond pairs, pi-bonds, and lone pairs on $\mathrm{Xe}$ Atoms Respectively are $5,3,0$.