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Question

Let y=log(log(x)) .Then find the value of eydydx.


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Solution

Compute the value of eydydx:

A function y=log(log(x)) is given.

Raise both sides to the power of the exponent.

So,

ey=elog(log(x))ey=log(x)[elogx=x]

Now, differentiate both sides with respect to x.

eydydx=1x.

Hence, the value of eydydx is 1x.


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