Question

Medicine is packed in boxes, each weighing $4\text{\hspace{0.17em}kg\hspace{0.17em}}500\text{\hspace{0.17em}gm}$. How many such boxes can be loaded in a can which cannot carry beyond $800\text{\hspace{0.17em}kg}$?

Answer 1

Step 1: Convert $\text{grams}$ into $\text{kilograms}$.

The weight of one box in $\text{kilograms}$ :

$\begin{array}{l}4\text{\hspace{0.17em}kg\hspace{0.17em}}500\text{\hspace{0.17em}gm}\\ =4\text{\hspace{0.17em}kg}+\frac{500}{1000}\text{\hspace{0.17em}kg}\\ =4\text{\hspace{0.17em}kg}+0.5\text{\hspace{0.17em}kg}\\ =4.5\text{\hspace{0.17em}kg}\end{array}[1\mathrm{kg}=1000\mathrm{gm}\Rightarrow 1\mathrm{gm}=\frac{1}{1000}\mathrm{kg}]$

Step 2: Calculate the number of boxes

The total weight allowed$=800\text{\hspace{0.17em}kg}$

Therefore, the number of boxes required:

$\begin{array}{l}\frac{\text{Total\hspace{0.17em}Weight}}{\text{Weight\hspace{0.17em}of\hspace{0.17em}one\hspace{0.17em}box}}\\ =\frac{800}{4.5}\\ =177.77\\ \approx 177\end{array}$

Hence, the total number of boxes that can hold $800\text{\hspace{0.17em}kg}$ is $177$.