Question

Multiply square root of $3$ and the square root of $6$.

Answer 1

Square root of $3$ is $\sqrt{3}$ and square root of $6$ is $\sqrt{6}$

If a natural number m can be expressed as $n^2$ , where $n$ is some integer, then $m$ is a square of $n$ and $n$is known as the square root of $m$.

The multiplication of the $\sqrt{3}$ and $\sqrt{6}$ is as follows:

$\begin{array}{c}\sqrt{3}\times \sqrt{6}=\sqrt{3\times 6}\\ \Rightarrow \sqrt{3}\times \sqrt{6}=\sqrt{3\times 3\times 2}\\ \Rightarrow \sqrt{3}\times \sqrt{6}=3\times \sqrt{2}\\ \Rightarrow \sqrt{3}\times \sqrt{6}=3\times 1.414\left[\because \sqrt{2}=1.414\right]\\ \Rightarrow \sqrt{3}\times \sqrt{6}=4.242\end{array}$

Hence, the result of the multiplication of the square root of $3$ and the square root of $6$ is $4.242$.