Solve: n2-3n4+5n6=21
Solving Linear Equations in One Variable.
Given equation: n2-3n4+5n6=21
The LCM of 2, 4 and 6 is 12.
Therefore, convert the terms on the LHS into like fractions with 12 as the denominator and simplify:
n×62×6-3n×34×3+5n×26×2=21⇒6n12-9n12+10n12=21⇒6n-9n+10n12=21⇒6n+n12=21⇒7n12=21⇒7n=21×12⇒n=21×127⇒n=3×121⇒n=36
Hence, the value of n is 36.
Solve linear equation:n2−3n4+5n6=21