Question

$\mathrm{N}-\mathrm{Ethyl}\mathrm{phthalimide}$ on hydrolysis gives:

• A. $\mathrm{methyl}\mathrm{alcohol}$
• B. $\mathrm{dimethyl}\mathrm{amine}$
• C. $\mathrm{diethyl}\mathrm{amine}$
• D. $\mathrm{ethyl}\mathrm{amine}$

Answer 1

The correct option is D

$\mathrm{ethyl}\mathrm{amine}$

The correct option is (D):-

Explanation for the correct answer:

Hydrolysis:-

1. It is actually a chemical breakdown of the substances by the use of water.
2. It depends upon the solubility, pH and oxidation-reduction potential of the particular compound.
3. In this process, there would be the splitting of a bond and this is by the addition of the Hydrogen cation $\left[{\mathrm{H}}^{+}\right]$ as well as the Hydroxide anions $\left[{\mathrm{OH}}^{-}\right]$ in the water.
4. Gabriel phthalimide synthesis is actually a process which is used for the preparation of the $1°$ amines.
5. In this synthesis, there is the involvement or the reaction of the Potassium salt of the Phthalimide, then further with the ethyl chloride which is followed by the hydrolysis for the production of $1°$ amine.
6. Through Gabriel phthalimide synthesis, Secondary or tertiary amines are not obtained as over alkylation is avoided.

Therefore, the correct option is (D):- $\mathrm{ethyl}\mathrm{amine}$