Question

The bond order of ${\mathrm{B}}_2$ molecule is _______.

Answer 1

Bond order:

• The number of chemical bonds between a pair of atoms is indicated by the bond order.
• Half of the difference between the number of electrons in bonding orbitals and antibonding orbitals is the Bond Order Formula.

$\mathrm{Bond}\mathrm{order}=\frac{1}{2}[{\mathrm{N}}_{\mathrm{b}}-{\mathrm{N}}_{\mathrm{a}}]$

Boron:

• The electrical configuration of the element boron (B) is as follows:

$$\begin{gathered} {\mathrm{B}}_2=\mathrm{\sigma }1{\mathrm{s}}^2,{\mathrm{\sigma }}^{*}1{\mathrm{s}}^2,\mathrm{\sigma }2{\mathrm{s}}^2,\mathrm{\sigma }*2{\mathrm{s}}^2,\left[\begin{array}{c}\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}^1\\ \mathrm{\pi }2{\mathrm{p}}_{\mathrm{z}}^1\end{array}\right] \\ \mathrm{Bond}\mathrm{order}=1/2[{\mathrm{N}}_{\mathrm{b}}–{\mathrm{N}}_{\mathrm{a}}] \\ =1/2[6-4] \\ =1 \end{gathered}$$