Numbers $1$ to $10$ are written on ten separate slips (Each number on different slip) , kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of getting a one-digit number ?

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Solution

Total number of slips in the box $= 10$
Number of slip containing a one-digit number $= \{1, 2, 3, 4, 5, 6, 7, 8, 9\} = 9$
We know that,
$P r o b a b i l i t y o f o c c u r i n g a n e v e n t = \frac{N u m b e r o f f a v o u r a b l e o u t c o m e}{T o t a l n u m b e r o f p o s s i b l e o u t c o m e}$
Total number of possible outcomes $=$ Total number of slips in the box $= 10$
Total number of favorable outcomes $=$ Number of slip containing a one-digit number $= 9$
Therefore,
Probability of getting a one-digit number on the slip $=$ $= \frac{N u m b e r o f f a v o r a b l e o u t c o m e}{T o t a l n u m b e r o f o u t c o m e} = \frac{9}{10}$
Hence, the probability of getting a one-digit number on the slip is $\frac{9}{10}$ .

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Numbers 1 to 10 are written on ten separate slips (Each number on different slip) , kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of getting a one-digit number ?

Numbers $1$ to $10$ are written on ten separate slips (Each number on different slip) , kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of getting a one-digit number ?