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Question

Numbers 1 to 5 are written on separate slips, one number on one slip and put in a box. Wahida pick a slip from the box without looking at it. What is the probability that the slip bears an odd number?


A

15

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B

25

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C

35

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D

45

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Solution

The correct option is C

35


Total number of slips in the box =5

Number of slip picked by Wahida from the box =1,3,5=3 ( As Wahida picks an odd number)

We know that,

ProbabilityofoccuringaneventPE=NumberoffavourableoutcomeTotalnumberofpossibleoutcome=nEnS

Total number of possible outcomes = Total number of slips in the box =nS=5

Total number of favorable outcomes =Number of slip picked by Wahida from the box =nE=3

Therefore,

Probability that the slip bears an odd number = =NumberoffavorableoutcomeTotalnumberofoutcome=nEnS=35

Hence, Probability that the slip bears an odd number is 35.


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