Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest ?

3.6

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Solution

The correct option is B 6
Let rate $= R %$ and time $= R$ years

Then, $(\frac{1200 \times R \times R}{100}) = 432$

$12 R^{2} = 432$

$R^{2} = 36$

$R = 6$

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Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest ?

The correct option is B 6Let rate =R% and time =R yearsThen, (1200×R×R100)=43212R2=432R2=36R=6

The correct option is B 6
Let rate $= R %$ and time $= R$ years

Then, $(\frac{1200 \times R \times R}{100}) = 432$

$12 R^{2} = 432$

$R^{2} = 36$

$R = 6$