Question

Simplify:$\left(\frac{7}{8}\right)+\left(\frac{1}{6}\right)-\left(\frac{1}{12}\right)$.

Answer 1

Simplify$\left(\frac{7}{8}\right)+\left(\frac{1}{6}\right)-\left(\frac{1}{12}\right)$.

BODMAS- It is a rule by which any expression is simplified. By this rule an expression in a sequence in which Bracket is solved first, then Off operation, then Division, then Multiplication, then Addition, and then finally Subtraction.

$\begin{array}{c}\left(\frac{7}{8}\right)+\left(\frac{1}{6}\right)-\left(\frac{1}{12}\right)=\left(\frac{7\times 3}{8\times 3}+\frac{1\times 4}{6\times 4}\right)-\frac{1}{12}\\ =\frac{21}{24}+\frac{4}{24}-\frac{1}{12}\\ =\frac{25}{24}-\frac{1}{12}\\ =\frac{25\times 1}{24\times 1}-\frac{1\times 2}{12\times 2}\\ =\frac{25}{24}-\frac{2}{24}\\ =\frac{23}{24}\end{array}$

Hence, the value of the given expression is $\left(\frac{7}{8}\right)+\left(\frac{1}{6}\right)-\left(\frac{1}{12}\right)=\frac{23}{24}$is $\frac{23}{24}$.