Question

$\mathrm{Sn}$ reacts with dil ${\mathrm{HNO}}_3$

Answer 1

Reaction of Tin(Sn) with ${\mathrm{HNO}}_3$:

Part 1: Reaction of Tin(Sn) with conc. ${\mathrm{HNO}}_3$

• Tin(Sn) reacts with concentrated Nitric acid to give metastannic acid, nitrogen oxide gas, and water.
• The balanced chemical reaction can be represented as:

$\underset{\mathrm{Tin}}{\mathrm{Sn}\left(\mathrm{s}\right)}+\underset{\mathrm{Nitric}\mathrm{acid}}{4{\mathrm{HNO}}_3\left(\mathrm{l}\right)}\to \underset{\mathrm{Metastannic}\mathrm{acid}}{{\mathrm{H}}_2{\mathrm{SnO}}_3\left(\mathrm{aq}\right)}+\underset{\mathrm{Nitric}\mathrm{oxide}}{4{\mathrm{NO}}_2\left(\mathrm{g}\right)}+\underset{\mathrm{Water}}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}$

Part 2: Reaction of Tin(Sn) with dil. ${\mathrm{HNO}}_3$

• Tin reacts with dilute Nitric acid to give Ammonium nitrate, water, and Tin nitrate.
• The balanced chemical reaction can be represented as:

$\underset{\mathrm{Tin}}{8\mathrm{Sn}}\left(s\right)+\underset{\mathrm{Nitric}\mathrm{acid}}{10{\mathrm{HNO}}_3\left(\mathrm{l}\right)}\to \underset{\mathrm{Ammonium}\mathrm{nitrate}}{{\mathrm{NH}}_4{\mathrm{NO}}_3\left(\mathrm{aq}\right)}+\underset{\mathrm{Tin}\mathrm{nitrate}}{8{\mathrm{SnNO}}_3\left(\mathrm{aq}\right)}+\underset{\mathrm{Water}}{3{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}$