Solve - 3x - 2 -4- 2x-3 -3- 2-3 - x

Given :(3x 2) /4 (2x+3) /3= 2/3 x=3(3x 2) 4(2x+3)/12=2 3x/3=9x 6 8x 12/12=2 3x/3⇒ x 18=4(2 3x)⇒ x 18=8 12x=x+12x = 8+18⇒ x=26/13⇒ x=2Hence x=2 is the corre ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Solving Equations with Variable on Both Sides

Solve : 3x - ...

Question

Solve :
$\frac{(3 x - 2)}{4} - \frac{(2 x + 3)}{3} = \frac{2}{3} - x$

Open in App

Solution

Given :
$\frac{(3 x - 2)}{4} - \frac{(2 x + 3)}{3} = \frac{2}{3} - x$
$= \frac{3 (3 x - 2) - 4 (2 x + 3)}{12} = \frac{2 - 3 x}{3}$
$= \frac{9 x - 6 - 8 x - 12}{12} = \frac{2 - 3 x}{3}$
$\Rightarrow x - 18 = 4 (2 - 3 x)$
$\Rightarrow x - 18 = 8 - 12 x$
$= x + 12 x = 8 + 18$
$\Rightarrow x = \frac{26}{13}$
$\Rightarrow x = 2$
Hence $x = 2$ is the correct answer.

Suggest Corrections

136

Similar questions

Q. Solve:

\frac{5}{x - 5} + \frac{2}{x - 2} = \frac{3}{x - 3} + \frac{4}{x - 4}

Q. Solve:

4 x^{2} + 4 \sqrt{3} x + 3 = 0

If $f = \frac{x}{1 + x^{2}} + \frac{1}{3} {(\frac{x}{1 + x^{2}})}^{3} + \frac{1}{5} {(\frac{x}{1 + x^{2}})}^{5} + . . .$ to $\infty$ and $g = x - \frac{2}{3} x^{3} + \frac{1}{5} x^{5} + \frac{1}{7} x^{7} - \frac{2}{9} x^{9} + . . .$ , then $f = d \times g$ . Find 4d.

Q. Solve:

\frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x

Q. Solve the following equation:

\sqrt{\frac{3 - x}{2 + x}} + 3 \sqrt{\frac{2 + x}{3 - x}} = 4

Join BYJU'S Learning Program

Solve : (3x-2)4-(2x+3)3=23-x

Given :(3x-2)4-(2x+3)3=23-x=3(3x-2)-4(2x+3)12=2-3x3=9x-6-8x-1212=2-3x3⇒x-18=4(2-3x)⇒x-18=8-12x=x+12x=8+18⇒x=2613⇒x=2Hence x=2 is the correct answer.

Solve :
$\frac{(3 x - 2)}{4} - \frac{(2 x + 3)}{3} = \frac{2}{3} - x$