Solve -a- 2 - 3 - 1 - 7 -b- 3 - 10 - 7 - 15 -c- 4 - 9 - 2 - 7 -d- 5 - 7 - 1 - 3 -e- 2 - 5 - 1 - 6 -f- 4 - 5 - 2 - 3 -g- 3 - 4 - 1 - 3 -h- 5 - 6 - 1 - 3 -i- 2 - 3 - 3 - 4 - 1 - 2 -j- 1- 2 - 1 - 3 - 1 - 6 - Maths Q-A

Solve the given fractions by taking L.C.M.Given that, 4/9+2/7LCM of ( 9 , 7 ) =63=[(4 × 7) + (2 × 9)] /630ex0ex= (28 + 18) /630ex0ex= 46/63Hence, 46/63is the ...

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Byju's Answer

Standard VI

Mathematics

Addition of Fractions

Solve (a) 2 /...

Question

Solve:
$\frac{4}{9} + \frac{2}{7}$

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Solution

Solve the given fractions by taking L.C.M.
Given that, $\frac{4}{9} + \frac{2}{7}$
LCM of $(9, 7) = 63$
$= \frac{[(4 \times 7) + (2 \times 9)]}{63} = \frac{(28 + 18)}{63} = \frac{46}{63}$
Hence, $\frac{46}{63}$ is the correct answer.

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Solve:49+27

Solve the given fractions by taking L.C.M.Given that, 49+27LCM of (9,7)=63=[(4×7)+(2×9)]63=(28+18)63=4663Hence, 4663is the correct answer.

Solve:
$\frac{4}{9} + \frac{2}{7}$

Solve the given fractions by taking L.C.M.
Given that, $\frac{4}{9} + \frac{2}{7}$
LCM of $(9, 7) = 63$
$= \frac{[(4 \times 7) + (2 \times 9)]}{63} = \frac{(28 + 18)}{63} = \frac{46}{63}$
Hence, $\frac{46}{63}$ is the correct answer.