Solve by substitution method:
3x+4y=10,2x-2y=2
By substitution method,
⇒2x-2y=2⇒2x-y=2⇒x-y=1⇒x=y+1
Substituting x=y+1 in other equation
⇒3x+4y=10⇒3y+1+4y=10⇒3y+3+4y=10⇒7y=10-3⇒7y=7⇒y=1
x=y+1⇒x=1+1⇒x=2
Hence, the value of x=2,y=1.
Question 1 (ii) Solve the following pair of linear equations by the elimination method and the substitution method: 3x + 4y = 10 and 2x - 2y = 2