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Question

Solve the following pair of linear equations by the substitution method:

3xy=39x3y=9.


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Solution

3x-y-3=0......(1)9x-3y-9=0......(2)

On comparing equation (1) and (2), we have

a1=3,b1=-1,c1=-3 and a2=9,b2=-3,c2=-9

39=-1-3=-3-913=13=13a1a2=b1b2=c1c2

Therefore, the given equations have infinitely many solutions.


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