Solve the quadratic equation x2+5x+6=0.
Given : x2+5x+6=0
⇒x2+2x+3x+6=0⇒x(x+2)+3(x+2)=0⇒(x+2)(x+3)=0Eitherx+2=0orx+3=0⇒x=-2orx=-3
Hence, x=-2orx=-3 is the solution of the given quadratic equation.