State and prove Gauss Theorem in electrostatics

Gauss’s Theorem Statement:

According to Gauss’s theorem the net-outward normal electric flux through any closed surface of any shape is equivalent to 1/ε0 times the total amount of charge contained within that surface.

Proof of Gauss’s Theorem Statement:

  • Let the charge be = q
  • Let us construct the Gaussian sphere of radius = r

Now, Consider , A surface or area ds having having ds (vector)

Normal having the flux at ds:

Flux at ds:

d e = E (vector) d s (vector) cos θ

But , θ = 0

Therefore, Total flux:

C = f d Φ

E 4 π r2

Therefore,

σ = 1 / 4πɛo q / r2 × 4π r2

σ = q / ɛo

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4 Comments

  1. Santanu borah Majuli

    Thank you so much

  2. On my online exam this question came and i didn’t study but I got help here
    Thank you

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