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Image in Thin Lens by Ray Tracing

Sudha finds o...

Question

Sudha finds out that the sharp image of the window pane of her science laboratory is formed at a distance of $15 c m$ from the lens. She now tries to focus the building visible to her outside the window instead of the window pane without disturbing the lens. In which direction will she move the screen to obtain a sharp image of the building? What is the approximate focal length of this lens?

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Solution

Explanation
We know that as the distance between the object and the viewer increase, the sharpness of the image decrease.
So to get a sharp image of the building Sudha should try to move the screen towards the lens.
The approximate focal length is $15 c m$
Hence, Sudha should try to move the screen towards the lens and the approximate focal length is $15 c m$

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Q. Sudha finds out that the sharp image of the window pane of her science laboratory is formed at a distance of

15 c m

from the lens. She now tries to focus the building visible to her outside the window instead of the window pane without disturbing the lens. In which direction will she move the screen to obtain a sharp image of the building? What is the approximate focal length of this lens?

Q. Question 26
Sudha finds out that the sharp image of the window pane of her science laboratory is formed at a distance of 15 cm from the lens. She now tries to focus the building visible to her outside the window instead of the window pane without disturbing the lens. In which direction will she move the screen to obtain a sharp image of the building? What is the approximate focal length of this lens?

Q. Sudha finds out that the sharp image of the window pane of her
science laboratory is formed at a distance of 15 cm from the lens.
She now tries to focus the building visible to her outside the window
instead of the window pane without disturbing the lens. In which
direction will she move the screen to obtain a sharp image of the
building?

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