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Question

(tanθ+2)(2tanθ+1)=5tanθ+sec2θ. Write ‘True’ or ‘False’ and justify your answer.


A
True
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B
False
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Solution

The correct option is B False

Trigonometric identity:

L.H.S.(tanθ+2)(2tanθ+1)

=2tan2θ+tanθ+4tanθ+2

=2tan2θ+5tanθ+2

=2sec2θ-1+5tanθ+2[1+tan2θ=sec2θ]

=2sec2θ-2+5tanθ+2 [1+tan2θ=sec2θ] =2sec2θ+5tanθ

R.H.S

L.H.SR.H.S

Hence, the given statement is false.


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