The 11th term of the AP- -5- -5-2- 0- 5-2- - is

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Formula for Sum of n Terms of an AP

The 11th term...

Question

The $11 t h$ term of the AP: $- 5, \frac{- 5}{2}, 0, \frac{5}{2}, \dots$ is

$- 20$

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$20$

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$- 30$

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$30$

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Solution

The correct option is B
$20$

We know that the $n t h$ term of an AP is given by the formula
$a_{n} = a + (n - 1) d$
where, $a$ is the first term, $a_{n}$ is the n^thterm, $d$ is the common difference
According to the question, we get
First-term, $a = - 5$
Common difference, $d = \frac{- 5}{2} - (- 5) = \frac{- 5}{2} + 5 = \frac{5}{2}$
Number of terms, $n = 11$
On substituting the values in the above formula, we get
$a_{11} = - 5 + (11 - 1) (\frac{5}{2})$
$\Rightarrow a_{11} = - 5 + 10 \times \frac{5}{2}$
$∴ a_{11} = - 5 + 25 = 20$

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Similar questions

(i) the sum fo the first n terms of an AP is $(\frac{5 n^{2}}{2} + \frac{3 n}{2})$ . Find hte nth term and the 20th term of this AP.
(ii) The sum of the first n terms of an AP is $(\frac{3 n^{2}}{2} + \frac{5 n}{2})$ . Find its nth term and the 25th term.

Find the 11th term of the A.P. $- 5, - \frac{5}{2}, 0, \frac{5}{2} . . . .$

Q. 11th term of the AP:

- 3, \frac{- 1}{2}, 2 . . .

Q. Question 4
The

11^{t h}

term of the AP

- 5, \frac{- 5}{2}, 0, \frac{5}{2}, \dots \dots

is

A) -20
B) 20
C) -30
D) 30

Find the $10 th$ term of the AP: sequence is $- 5, \frac{- 5}{2}, 0, \frac{5}{2} . . . . .$

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The 11th term of the AP: -5,-52,0,52,… is

The $11 t h$ term of the AP: $- 5, \frac{- 5}{2}, 0, \frac{5}{2}, \dots$ is