Question

The ${2006}^{th}$ digit in the sequence $12345678910111213$ is

Answer 1

The number of $1$ digit numbers $=9$

Number of $2$ digit numbers $=90$

Number of $3$ digit numbers starting from $100$ till $699$ $=600$ (to find the number of digits, then multiply by $3$)

Beginning from $1$ to $699$, the total number of digits will be $9+2\times 90+3\times 600=1989$.

Add $700–704$ and get total $1989+15=2004$ digits enlisted.

The $2006$ digit in the sequence is clearly evident that it would be the second digit of $705$ which is $0$.

Hence, the ${2006}^{th}$ digit in the sequence $12345678910111213$ is $0$.