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Question

The acceleration of a particle is seen from two frames S1​ and S2 have an equal magnitude of 5ms-2. then


A

The acceleration of frame ​ with respect S2 to S1​ be 0 or 10ms-2

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B

The acceleration of frame S2​ with respect to S1​ lies between 0 and 10ms-2

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C

The frames may be moving with respect to each other but neither should be accelerated with respect to the other.

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D

The frames must be at rest with respect to each other.

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Solution

The correct option is B

The acceleration of frame S2​ with respect to S1​ lies between 0 and 10ms-2


Step 1. Given data

  1. S1 and S2 is of equal magnitude
  2. S1=S2=5m/s2

Step 2. Formula used

Consider a vector v represented by AB side of the parallelogram and the vector u represented by AD of the parallelogram ABCD then the resultant vector w represented by AC is

w=u2+v2-2·u·v·cosφ

Step 3. Find the acceleration of frame S2​ with respect to S1

Using parallelogram law,

Let S1​ and S2 are the two arms of the parallelogram

Given S1=S2=5m/s2

The angle between the two vectors may lie between 0° to 180°

The resultant when the angle is 0° is

R=S12+S22-2·S1·S2·cosθ=52+52-2·5·5cos0°=50-50=0

The resultant when the angle is 180° is

R=S12+S22-2·S1·S2·cosθ=52+52-2·5·5cos180°=50+50=10

Therefore the acceleration of the frame S2​ with respect to S1​ lies between 0 and 10ms-2.

Hence, Option B is correct


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