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Question

The area of a square field is 9hectares. A man cycles along its boundary at18km/h. In how much time will he return to starting point?


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Solution

Step 1: Finding the side of the square field

Given

Area of the square field =9hectare=90000m2(since1hectare=10000m2)

We know that

Areaofsquare=side2

Let a be the side of the square.

Then,

a2=90000m2

Soa=90000=300m

Thus, the side of the square is 300m

Step 2: Finding the perimeter of the square field

We know that,

Perimeterofsquare=4×side=4×300=1200m

Step 3: Finding the time taken to complete the boundary of the field

Speedofman=18km/h=18×518m/s=5m/s

We know that,

time=distancespeed

So,

Time is taken to cover the distance 1200m is

=12005=240seconds

Hence, the man will return to the starting point in 240seconds.


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