The class mark of the class $90 - 120$ is

$90$

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$105$

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$115$

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$120$

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Solution

The correct option is B
$105$

Findng the class mark:
We know that,
$C l a s s m a r k = \frac{L o w e r l i m i t + u p p e r l i m i t}{2}$
From the given data upper limit $= 120$ and lower limit $= 90$
Class mark $=$ $\frac{120 + 90}{2}$
$= \frac{120}{2} = 105$
Therefore, the class mark $90 - 120$ is $105$ .

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Similar questions

Question 1
The class mark of class 90 - 120 is:

A) 90
B) 105
C) 115
D) 120

Q. The class mark of the class 100−120 is
(a) 100
(b) 110
(c) 115
(d) 120

(i) Find the class mark of the class 90-120.
(ii) In a frequency distribution, the mid-value of the class is 10 and width of the class is 6. Find the lower limit of the class.
(iii) The width of each of five continuous classes in a frequency distribution is 5 and lower class limit of the lowest class is 10. What is the upper class limit of the highest class?
(iv) The class marks of a frequency distribution are 15, 20, 25, .... Find the class corresponding to the class mark 20.
(v) In the class intervals 10-20, 20-30, find the class in which 20 is included.

The class mark of the class $90 - 120$ is:

Q. For the given class of 90-120, the class mark is ______ .

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The class mark of the class 90-120 is

The correct option is B 105Findng the class mark:We know that,Classmark=Lowerlimit+upperlimit2From the given data upper limit=120 and lower limit =90Class mark= 120+902 =1202=105Therefore, the class mark 90-120 is 105.

The class mark of the class $90 - 120$ is