The conjugate complex number of (2-i)/(1-2i)2 is

Solution:

(2-i)/(1-2i)2 = (2-i)/(1-4i-4)

= (2-i)/(-3-4i)

= (-2+i)/(3+4i)

Multiply numerator and denominator with (3-4i)

=> (-2+i)(3-4i)/(3+4i)(3-4i) = (-6+3i+8i+4)/(9+16)

= (-2+11i)/25

Conjugate of (-2+11i)/25 is (-2-11i)/25.

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