Question

The cost of $2kg$ of apples and $1kg$ of grapes on a day was found to be $₹160$. After a month, the cost of $4kg$ of apples and $2kg$ of grapes is $₹300$. Represent the situation algebraically and geometrically.

Answer 1

Let the cost of $1kg$ of apples be $₹x$

And, cost of $1kg$ of grapes be $₹y$

According to the given condition the algebraic representation is

$$\begin{gathered} 2x+y=160 \\ 4x+2y=300 \end{gathered}$$

For, $2x+y=160$ or $y=160-2x$, the solution table is

$x$	$50$	$60$	$70$
$y$	$60$	$60$	$20$

For$4x+2y=300$ or $y=\frac{300-4x}{2}$, the solution table is

$x$	$70$	$80$	$75$
$y$	$10$	$-10$	$0$

The equation can be graphically represented as