Question

The digit in the tens place of a two digit number is $3$ more than the digit in the units place. Let the digit at units place be $b$. Then the number is

• A. $11b+30$
• B. $10b+30$
• C. $10b+3$
• D. $11b+3$

Answer 1

The correct option is A

$11b+30$

Determine the number.

Explanation for correct option:

Option (A) : $11b+30$

The digit at the ones place is $b$.

Let the digit at the tens place be $a$.

So, the number is $10a+b$.

The digit at the tens place is $3$ more than $b$. i.e.$a=b+3$

Substitute this expression into $10a+b$:

$10\left(b+3\right)+b=11b+30$

So, option (A) is correct.

Explanation for incorrect options:

Since the expression of the number is $11b+30$, which is not equivalent to the expression mentioned options (B), Option (C), and Option (D) are incorrect.

Hence, the correct option is Option (A)