The edges of a triangular board are $3 m, 4 m a n d 5 m .$ The cost of painting it at the rate of $R s . 40 a n d 50 p a i s a p e r m^{2}$

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Solution

Given sides of the triangular board are $3 m, 4 m a n d 5 m .$
This is a right-angled triangle.
Base $= 4 m$
Height $= 3 m$
Area of triangle $= \frac{1}{2} \times b \times h$
$= \frac{1}{2} \times 4 \times 3 = 6 m^{2}$
Cost of painting a wall per meter square $= 40.50$
The total cost of painting a wall $= 6 \times 40.50$
$= R s . 243$
Hence, the total cost of painting the wall is $R s . 243$

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