Question

The element with atomic number $14$ is hard and forms acidic oxide and a covalent halide. To which of the following categories does the element belong?

• A. Metal
• B. Metalloid
• C. Nonmetal
• D. Left-hand side element

Answer 1

The correct option is B

Metalloid

Explanation for correct option

(B)Metalloid

• Metalloids are the elements that are a mid-way between metals and non-metals.
• Element with atomic number $14$ is Silicon and is a metalloid.
• Silicon is the p-block element.
• It is the right-hand side element.
• It forms an acidic oxide, thus behaving as a non-metal.
• It also forms a covalent halide, thus acting as a metal.

Explanation for incorrect option

Metal

• Metals, in their pure state, have a shining surface. This property is called metallic luster.
• Metals are found on the left side of the periodic table.
• Metals are generally hard.
• Metals are usually solids at room temperature

Nonmetals

• Non-metals are found in the Periodic Table's top right corner.
• In fact, in a horizontal row, the property of elements changes from metallic on the left to non-metallic on the right.
• Non-metals are usually solids or gases at room temperature with low boiling and melting points(boron and carbon are exceptions).
• They are poor conductors of heat and electricity.
• Most nonmetallic solids are brittle and are neither malleable nor ductile.

Hence, options (A), (C), and (D) are incorrect.

Hence, option (B) is correct. So, the element belongs to the metalloid.