Question

The equivalent weight of ${\mathrm{MnSO}}_4$ is half of its molecular weight when it is converted to?

Answer 1

Step 1: Equivalent mass:

• Equivalent mass is equal to the molecular/atomic mass divided by the number of electrons involved in the reaction per molecule/atom/ion.
• It is expressed as:

$\mathrm{Equivalent}\mathrm{mass}=\frac{\mathrm{Atomic}\mathrm{mass}}{\mathrm{Valency}\mathrm{factor}}$

Step 2: Conversion of Manganese sulfate to Manganese oxide:

• To get the equivalent weight half of molecular weight, the following conversion will take place.

${\mathrm{Mn}}^{+2}{\mathrm{SO}}_4^{-2}\to {\mathrm{Mn}}^{+4}{\mathrm{O}}_2+2{\mathrm{e}}^{-}$

• Here the valency factor is $2$, so the equivalent weight will be :

Step 3: Calculation for equivalent mass:

$\mathrm{Equivalent}\mathrm{weight}=\frac{\mathrm{M}}{2}$

Here, $\mathrm{M}$= molecular weight.

Hence, the equivalent weight of ${\mathrm{MnSO}}_4$ is half of its molecular weight when it is converted to ${\mathrm{MnO}}_2$.