The expansion of ${(3 x - 2 y)}^{3}$ is

Open in App

Solution

Solving an equation:
The given expression is of the form ${(a - b)}^{3} = a^{3} - b^{3} - 3 a^{2} b + 3 a b^{2}$
$∴ {(3 x - 2 y)}^{3} = {(3 x)}^{3} - {(2 y)}^{3} - 3 {(3 x)}^{2} (2 y) + 3 (3 x) {(2 y)}^{2} = 27 x^{3} - 8 y^{3} - 54 x^{2} y + 36 x y^{2}$
Hence, the expansion of ${(3 x - 2 y)}^{3} = 27 x^{3} - 8 y^{3} - 54 x^{2} y + 36 x y^{2}$

Suggest Corrections

Similar questions

Find the 8th term in the expansion of $(x^{3 / 2} y^{1 / 2} - x^{1 / 2} y^{3 / 2})^{10} .$

Factorize $(3 x - 2 y)^{3} + (2 y - 4 z)^{3} + (4 z - 3 x)^{3}$

(3 x - 2 y)^{3}

Join BYJU'S Learning Program