Question

The gas liberated by heating potassium permanganate $\left({\mathrm{KMnO}}_4\right)$ is:

• A. Hydrogen
• B. Oxygen
• C. Nitrogen
• D. Methane

Answer 1

The correct option is B

Oxygen

The explanation for the correct option

(B) Oxygen

Potassium permanganate

• Potassium permanganate decomposes at 513 K on heating.
• On heating Potassium permanganate, the formation of Potassium manganate, manganese dioxide, and oxygen gas takes place.

Chemical reaction

• The chemical reaction is as follows:-
• $2{\text{KMnO}}_4\left(\text{s}\right)\stackrel{∆}{\to }{\text{K}}_{\text{2}}{\text{MnO}}_{\text{4}}\left(\text{s}\right)+{\text{MnO}}_2\left(\text{s}\right)+{\text{O}}_2\left(\text{g}\right)$

Hence, gas liberated by heating potassium permanganate $\left({\mathrm{KMnO}}_4\right)$ is oxygen.

The explanation for the incorrect options

The gas liberated by heating potassium permanganate $\left({\mathrm{KMnO}}_4\right)$ is oxygen. Hence, options (A), (C), and (D) are incorrect.

Thus, the correct option is (B).