The hypotenuse of a right triangle with its legs of lengths $3 x \times 4 x$ is

$5 x$

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$7 x$

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$16 x$

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$25 x$

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Solution

The correct option is A
$5 x$

By the Pythagorean theorem $= a = \sqrt{(b^{2} + c^{2})}$
Given $b = 3 x a n d c = 4 x$
$a = \sqrt{({(3 x)}^{2} + {(4 x)}^{2})} a = \sqrt{(9 x^{2} + 16 x^{2})} a = \sqrt{25 x^{2}} a = 5 x$
Hence, the hypotenuse of the right triangle is $5 x .$

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Similar questions

Question 14

Write the correct answer from the given four options.

The hypotenuse of a right-angled triangle with its legs of lengths $3 x \times 4 x$ is

a) 5x
b) 7x
c) 16x
d) 25x

△ A B C

a = 6 c m

b = 4.5 c m

50 {c m}^{2}

sin θ + sin (\frac{3 π}{2} - θ)

cos θ - cos (\frac{3 π}{2} - θ)

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