Question

The lengths of 62 leaves of a plant are measured in millimetres and the data is represented in the following table. Draw a histogram to represent the data above.

Length (in mm)	Number of leaves
$118-126$	$8$
$127-135$	$10$
$136-144$	$12$
$145-153$	$17$
$154-162$	$7$
$163-171$	$5$
$172-180$	$3$

Answer 1

Step 1: Calculate the frequency distribution

Given, that the length of 62 leaves of a plant measured in millimeters

The table represents the length of leaves and the number of leaves

We have to draw a histogram for the given data.

The given frequency distribution is in the inclusive form.

On converting to exclusive form,

Now, consider the classes $118-126\mathrm{and}127-135$

The lower limit of $127-135\mathrm{is}127.$

The upper limit of $118-126\mathrm{is}126.$

Half the difference between the lower and upper limit

$$\begin{gathered} =\frac{(127-126)}{2} \\ =0.5 \end{gathered}$$

Thus, we subtract $0.5$ from each lower limit and add $0.5$ to each upper limit.

Step 2: Construct the table for continuous grouped frequency distribution

The table for continuous grouped frequency distribution becomes,

Length (in mm)	Number of leaves
$117.5-126.5$	$8$
$126.5-135.5$	$10$
$135.5-144.5$	$12$
$144.5-153.5$	$17$
$153.5-162.5$	$7$
$162.5-171.5$	$5$
$171.5-180.5$	$3$

Thus, the given data becomes in the exclusive form.
Step 3: Plot the histogram for the given table of data

Along the horizontal axis, we represent the class intervals of length on some suitable scale.
The corresponding frequencies of the number of leaves are represented along the Y-axis on a suitable scale.
The given intervals start with $117.5-126.5$

It means that there is some break (≈) indicated near the origin to signify the graph is drawn with a scale beginning at $117.5$

Hence, a histogram for the class interval of length and the corresponding frequencies of the number of leaves of a plant with $\mathbf{62}\mathbf{}$leaves is mentioned above