Question

The loss percent on selling $140$ geometry boxes at the loss of S.P. of $10$ geometry boxes is equal to _____

Answer 1

Calculate the loss percent:

Let the selling price of one geometry box is $m$.

$\therefore$ the selling price of $140$ geometry boxes$=140m$

$$\begin{gathered} \because \mathrm{Loss}=\mathrm{S}.\mathrm{P}\mathrm{of}10\mathrm{boxes} \\ \Rightarrow =10m \end{gathered}$$

As we know,

$$\begin{gathered} \mathrm{Cost}\mathrm{price}=\mathrm{S}.\mathrm{P}+\mathrm{Loss} \\ \Rightarrow =140m+10m \\ \Rightarrow =150m \end{gathered}$$

The loss percent is computed as,

$$\begin{gathered} \therefore \mathrm{Loss}\%=\frac{\mathrm{Loss}}{\mathrm{C}.\mathrm{P}.}\times 100 \\ \Rightarrow =\frac{10m}{150m}\times 100 \\ \Rightarrow =\frac{20}{3} \\ \Rightarrow =6\frac{2}{3}\% \end{gathered}$$

Hence, the loss percent is equal to $6\frac{2}{3}\%$.