Question

The moment of a magnet $(15cm\times 2cm\times 1cm)$ is $1.2A{m}^2$. What is its intensity of magnetization?

Answer 1

Step 1: Given data

Dimensions of magnet = $15cm\times 2cm\times 1cm$

$\Rightarrow$The volume of the magnet, $V=15cm\times 2cm\times 1cm$

Moment of the magnet, $M=1.2A{m}^2$

Step 2: Formula used and substitution

The intensity of magnetization, $I_m=\frac{M}{V}$

$\Rightarrow I_m=\frac{M}{V}$

$\Rightarrow I_m=\frac{1.2A{m}^2}{15cm\times 2cm\times 1cm}$

$\Rightarrow I_m=\frac{1.2A{m}^2}{15\times 2\times 1\times {10}^{-6}{m}^3}$

$\Rightarrow I_m=4\times {10}^{4}A{m}^{-1}$

Thus, the intensity of magnetization is $I_m=4\times {10}^{4}A{m}^{-1}$