Question

The oxide of an element possesses the formula ${\text{M}}_{\text{2}}{\text{O}}_{\text{3}}$. If the equivalent weight of the metal is 9, then the atomic weight of the metal will be?

Answer 1

Step1. The formula of equivalent weight

$\text{Equivalent weight of the metal = Atomic weight of the metal / valency}$

Step2. Calculation of atomic weight

• The formula of the oxide is ${\text{M}}_{\text{2}}{\text{O}}_{\text{3}}$.
• So, the valency of the Metal = $3$.

$$\begin{gathered} \text{9 =}\frac{\text{Atomic weight of metal}}{3} \\ \text{Atomic weight of metal=9×3} \\ =27 \end{gathered}$$

So, the atomic weight of the metal will be $27$.