The pair of compounds that can exist together is

F e C l_{3}, S n C l_{2}

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H g C l_{2}, S n C l_{2}

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F e C l_{2}, S n C l_{2}

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F e C l_{3}, K I

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Solution

The correct option is C $F e C l_{2}, S n C l_{2}$
Both $F e C l_{2}$ and $S n C l_{2}$ are reducing agents with low oxidation numbers.

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